Base | Representation |
---|---|
bin | 11101111110111010111… |
… | …11000110010111001011 |
3 | 10122111011022200222110220 |
4 | 32333131133012113023 |
5 | 113334334023213003 |
6 | 2105135014041123 |
7 | 134300432605422 |
oct | 16773537062713 |
9 | 3574138628426 |
10 | 1030213101003 |
11 | 367a0248a959 |
12 | 1477b43491a3 |
13 | 761c18540b8 |
14 | 37c10cc42b9 |
15 | 1bbe8e36353 |
hex | efdd7c65cb |
1030213101003 has 4 divisors (see below), whose sum is σ = 1373617468008. Its totient is φ = 686808734000.
The previous prime is 1030213100963. The next prime is 1030213101023. The reversal of 1030213101003 is 3001013120301.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1030213101003 - 233 = 1021623166411 is a prime.
It is a super-2 number, since 2×10302131010032 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1030213101023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171702183498 + ... + 171702183503.
It is an arithmetic number, because the mean of its divisors is an integer number (343404367002).
Almost surely, 21030213101003 is an apocalyptic number.
1030213101003 is a deficient number, since it is larger than the sum of its proper divisors (343404367005).
1030213101003 is an equidigital number, since it uses as much as digits as its factorization.
1030213101003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 343404367004.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 1030213101003 its reverse (3001013120301), we get a palindrome (4031226221304).
The spelling of 1030213101003 in words is "one trillion, thirty billion, two hundred thirteen million, one hundred one thousand, three".
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