103021415551441 has 4 divisors (see below), whose sum is σ = 103021535472484. Its totient is φ = 103021295630400.

The previous prime is 103021415551433. The next prime is 103021415551447. The reversal of 103021415551441 is 144155514120301.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 21637940755600 + 81383474795841 = 4651660^2 + 9021279^2 .

It is a cyclic number.

It is not a de Polignac number, because 103021415551441 - 2³ = 103021415551433 is a prime.

It is a super-2 number, since 2×103021415551441² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 103021415551441.

It is not an unprimeable number, because it can be changed into a prime (103021415551447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58662540 + ... + 60393181.

It is an arithmetic number, because the mean of its divisors is an integer number (25755383868121).

Almost surely, 2^{103021415551441} is an apocalyptic number.

It is an amenable number.

103021415551441 is a deficient number, since it is larger than the sum of its proper divisors (119921043).

103021415551441 is an equidigital number, since it uses as much as digits as its factorization.

103021415551441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 119921042.

The product of its (nonzero) digits is 48000, while the sum is 37.

Adding to 103021415551441 its reverse (144155514120301), we get a palindrome (247176929671742).

The spelling of 103021415551441 in words is "one hundred three trillion, twenty-one billion, four hundred fifteen million, five hundred fifty-one thousand, four hundred forty-one".