10303130013011 has 4 divisors (see below), whose sum is σ = 11239778196024. Its totient is φ = 9366481830000.

The previous prime is 10303130012963. The next prime is 10303130013013. The reversal of 10303130013011 is 11031003130301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10303130013011 - 2¹⁸ = 10303129750867 is a prime.

It is a super-3 number, since 3×10303130013011³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10303130013013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 468324091490 + ... + 468324091511.

It is an arithmetic number, because the mean of its divisors is an integer number (2809944549006).

Almost surely, 2^{10303130013011} is an apocalyptic number.

10303130013011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

10303130013011 is a deficient number, since it is larger than the sum of its proper divisors (936648183013).

10303130013011 is an equidigital number, since it uses as much as digits as its factorization.

10303130013011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 936648183012.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 10303130013011 its reverse (11031003130301), we get a palindrome (21334133143312).

The spelling of 10303130013011 in words is "ten trillion, three hundred three billion, one hundred thirty million, thirteen thousand, eleven".