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103040113 = 1110978539
BaseRepresentation
bin1100010010001…
…00010001110001
321011212222110111
412021010101301
5202334240423
614120301321
72360553331
oct611042161
9234788414
10103040113
1153188620
122a611841
13184694a7
14d9830c1
1590a560d
hex6244471

103040113 has 8 divisors (see below), whose sum is σ = 112523040. Its totient is φ = 93576480.

The previous prime is 103040087. The next prime is 103040149. The reversal of 103040113 is 311040301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 103040113 - 25 = 103040081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103040093 and 103040102.

It is not an unprimeable number, because it can be changed into a prime (103044113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7798 + ... + 16336.

It is an arithmetic number, because the mean of its divisors is an integer number (14065380).

Almost surely, 2103040113 is an apocalyptic number.

It is an amenable number.

103040113 is a deficient number, since it is larger than the sum of its proper divisors (9482927).

103040113 is a wasteful number, since it uses less digits than its factorization.

103040113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9647.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 103040113 is about 10150.8675983878. The cubic root of 103040113 is about 468.8156585242.

Adding to 103040113 its reverse (311040301), we get a palindrome (414080414).

The spelling of 103040113 in words is "one hundred three million, forty thousand, one hundred thirteen".

Divisors: 1 11 1097 8539 12067 93929 9367283 103040113