Base | Representation |
---|---|
bin | 101111111110110101… |
… | …0111100111010100011 |
3 | 100211222001012121110000 |
4 | 1133331222330322203 |
5 | 3142011234034021 |
6 | 115200323511043 |
7 | 10305300523131 |
oct | 1377552747243 |
9 | 324861177400 |
10 | 103040143011 |
11 | 3a776524593 |
12 | 17b77b28483 |
13 | 994160a930 |
14 | 4db6b16751 |
15 | 2a310acb26 |
hex | 17fdabcea3 |
103040143011 has 80 divisors (see below), whose sum is σ = 181178097408. Its totient is φ = 57753907200.
The previous prime is 103040143007. The next prime is 103040143013. The reversal of 103040143011 is 110341040301.
It is not a de Polignac number, because 103040143011 - 22 = 103040143007 is a prime.
It is a super-2 number, since 2×1030401430112 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (103040143013) by changing a digit.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 462091 + ... + 647771.
Almost surely, 2103040143011 is an apocalyptic number.
103040143011 is a deficient number, since it is larger than the sum of its proper divisors (78137954397).
103040143011 is a wasteful number, since it uses less digits than its factorization.
103040143011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 185754 (or 185745 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 103040143011 its reverse (110341040301), we get a palindrome (213381183312).
It can be divided in two parts, 103040 and 143011, that added together give a triangular number (246051 = T701).
The spelling of 103040143011 in words is "one hundred three billion, forty million, one hundred forty-three thousand, eleven".
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