103040143131 has 4 divisors (see below), whose sum is σ = 137386857512. Its totient is φ = 68693428752.

The previous prime is 103040143123. The next prime is 103040143177. The reversal of 103040143131 is 131341040301.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 103040143131 - 2³ = 103040143123 is a prime.

It is a super-2 number, since 2×103040143131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103040143098 and 103040143107.

It is not an unprimeable number, because it can be changed into a prime (103040143831) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17173357186 + ... + 17173357191.

It is an arithmetic number, because the mean of its divisors is an integer number (34346714378).

Almost surely, 2^103040143131 is an apocalyptic number.

103040143131 is a deficient number, since it is larger than the sum of its proper divisors (34346714381).

103040143131 is an equidigital number, since it uses as much as digits as its factorization.

103040143131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34346714380.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 103040143131 its reverse (131341040301), we get a palindrome (234381183432).

The spelling of 103040143131 in words is "one hundred three billion, forty million, one hundred forty-three thousand, one hundred thirty-one".