1030441120131 has 4 divisors (see below), whose sum is σ = 1373921493512. Its totient is φ = 686960746752.

The previous prime is 1030441120117. The next prime is 1030441120139. The reversal of 1030441120131 is 1310211440301.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1030441120131 - 2²⁶ = 1030374011267 is a prime.

It is a super-2 number, since 2×1030441120131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1030441120098 and 1030441120107.

It is not an unprimeable number, because it can be changed into a prime (1030441120139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171740186686 + ... + 171740186691.

It is an arithmetic number, because the mean of its divisors is an integer number (343480373378).

Almost surely, 2^{1030441120131} is an apocalyptic number.

1030441120131 is a deficient number, since it is larger than the sum of its proper divisors (343480373381).

1030441120131 is an equidigital number, since it uses as much as digits as its factorization.

1030441120131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 343480373380.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 1030441120131 its reverse (1310211440301), we get a palindrome (2340652560432).

The spelling of 1030441120131 in words is "one trillion, thirty billion, four hundred forty-one million, one hundred twenty thousand, one hundred thirty-one".