10304424131 has 4 divisors (see below), whose sum is σ = 10305398664. Its totient is φ = 10303449600.

The previous prime is 10304424121. The next prime is 10304424157. The reversal of 10304424131 is 13142440301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10304424131 is a prime.

It is a super-2 number, since 2×10304424131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10304424097 and 10304424106.

It is not an unprimeable number, because it can be changed into a prime (10304424121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 471230 + ... + 492611.

It is an arithmetic number, because the mean of its divisors is an integer number (2576349666).

Almost surely, 2^10304424131 is an apocalyptic number.

10304424131 is a deficient number, since it is larger than the sum of its proper divisors (974533).

10304424131 is an equidigital number, since it uses as much as digits as its factorization.

10304424131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 974532.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 10304424131 its reverse (13142440301), we get a palindrome (23446864432).

The spelling of 10304424131 in words is "ten billion, three hundred four million, four hundred twenty-four thousand, one hundred thirty-one".