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10305053131 = 25740097483
BaseRepresentation
bin10011001100011101…
…01010000111001011
3222121011202221100111
421212032222013023
5132101043200011
64422321015151
7513240335452
oct114616520713
928534687314
1010305053131
114408a2aa3a
121bb71844b7
13c82c67299
146da88db99
15404a69121
hex2663aa1cb

10305053131 has 4 divisors (see below), whose sum is σ = 10345150872. Its totient is φ = 10264955392.

The previous prime is 10305053063. The next prime is 10305053141. The reversal of 10305053131 is 13135050301.

10305053131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10305053131 is a prime.

It is a super-2 number, since 2×103050531312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10305053141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20048485 + ... + 20048998.

It is an arithmetic number, because the mean of its divisors is an integer number (2586287718).

Almost surely, 210305053131 is an apocalyptic number.

10305053131 is a deficient number, since it is larger than the sum of its proper divisors (40097741).

10305053131 is an equidigital number, since it uses as much as digits as its factorization.

10305053131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40097740.

The product of its (nonzero) digits is 675, while the sum is 22.

The spelling of 10305053131 in words is "ten billion, three hundred five million, fifty-three thousand, one hundred thirty-one".

Divisors: 1 257 40097483 10305053131