103104129433 has 4 divisors (see below), whose sum is σ = 103235139280. Its totient is φ = 102973119588.

The previous prime is 103104129371. The next prime is 103104129437. The reversal of 103104129433 is 334921401301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 103104129433 - 2⁹ = 103104128921 is a prime.

It is a super-2 number, since 2×103104129433² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103104129395 and 103104129404.

It is not an unprimeable number, because it can be changed into a prime (103104129437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65503743 + ... + 65505316.

It is an arithmetic number, because the mean of its divisors is an integer number (25808784820).

Almost surely, 2^103104129433 is an apocalyptic number.

It is an amenable number.

103104129433 is a deficient number, since it is larger than the sum of its proper divisors (131009847).

103104129433 is an equidigital number, since it uses as much as digits as its factorization.

103104129433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 131009846.

The product of its (nonzero) digits is 7776, while the sum is 31.

The spelling of 103104129433 in words is "one hundred three billion, one hundred four million, one hundred twenty-nine thousand, four hundred thirty-three".