10311133122131 has 4 divisors (see below), whose sum is σ = 10380335358000. Its totient is φ = 10241930886264.

The previous prime is 10311133122113. The next prime is 10311133122163. The reversal of 10311133122131 is 13122133111301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10311133122131 - 2⁴² = 5913086611027 is a prime.

It is a super-2 number, since 2×10311133122131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10311133122097 and 10311133122106.

It is not an unprimeable number, because it can be changed into a prime (10311133112131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34601117711 + ... + 34601118008.

It is an arithmetic number, because the mean of its divisors is an integer number (2595083839500).

Almost surely, 2^{10311133122131} is an apocalyptic number.

10311133122131 is a deficient number, since it is larger than the sum of its proper divisors (69202235869).

10311133122131 is an equidigital number, since it uses as much as digits as its factorization.

10311133122131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69202235868.

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 10311133122131 its reverse (13122133111301), we get a palindrome (23433266233432).

The spelling of 10311133122131 in words is "ten trillion, three hundred eleven billion, one hundred thirty-three million, one hundred twenty-two thousand, one hundred thirty-one".