10311210312113 has 4 divisors (see below), whose sum is σ = 10759523803968. Its totient is φ = 9862896820260.

The previous prime is 10311210312107. The next prime is 10311210312131. The reversal of 10311210312113 is 31121301211301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10311210312113 - 2³⁰ = 10310136570289 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10311210311113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224156745893 + ... + 224156745938.

It is an arithmetic number, because the mean of its divisors is an integer number (2689880950992).

Almost surely, 2^{10311210312113} is an apocalyptic number.

It is an amenable number.

10311210312113 is a deficient number, since it is larger than the sum of its proper divisors (448313491855).

10311210312113 is an equidigital number, since it uses as much as digits as its factorization.

10311210312113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 448313491854.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 10311210312113 its reverse (31121301211301), we get a palindrome (41432511523414).

The spelling of 10311210312113 in words is "ten trillion, three hundred eleven billion, two hundred ten million, three hundred twelve thousand, one hundred thirteen".