10311231113 has 4 divisors (see below), whose sum is σ = 10312078848. Its totient is φ = 10310383380.

The previous prime is 10311231103. The next prime is 10311231121. The reversal of 10311231113 is 31113211301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31113211301 = 12739 ⋅2442359.

It is a cyclic number.

It is not a de Polignac number, because 10311231113 - 2⁸ = 10311230857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10311231091 and 10311231100.

It is not an unprimeable number, because it can be changed into a prime (10311231103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 405353 + ... + 430038.

It is an arithmetic number, because the mean of its divisors is an integer number (2578019712).

Almost surely, 2^10311231113 is an apocalyptic number.

It is an amenable number.

10311231113 is a deficient number, since it is larger than the sum of its proper divisors (847735).

10311231113 is an equidigital number, since it uses as much as digits as its factorization.

10311231113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 847734.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 10311231113 its reverse (31113211301), we get a palindrome (41424442414).

The spelling of 10311231113 in words is "ten billion, three hundred eleven million, two hundred thirty-one thousand, one hundred thirteen".