10311300000033 has 8 divisors (see below), whose sum is σ = 13754354275200. Its totient is φ = 6871222862448.

The previous prime is 10311300000013. The next prime is 10311300000037. The reversal of 10311300000033 is 33000000311301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10311300000033 - 2³⁶ = 10242580523297 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10311299999958 and 10311300000021.

It is not an unprimeable number, because it can be changed into a prime (10311300000037) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 744276313 + ... + 744290166.

It is an arithmetic number, because the mean of its divisors is an integer number (1719294284400).

Almost surely, 2^{10311300000033} is an apocalyptic number.

It is an amenable number.

10311300000033 is a deficient number, since it is larger than the sum of its proper divisors (3443054275167).

10311300000033 is a wasteful number, since it uses less digits than its factorization.

10311300000033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1488568791.

The product of its (nonzero) digits is 81, while the sum is 15.

Adding to 10311300000033 its reverse (33000000311301), we get a palindrome (43311300311334).

The spelling of 10311300000033 in words is "ten trillion, three hundred eleven billion, three hundred million, thirty-three", and thus it is an aban number.