10311345131 has 4 divisors (see below), whose sum is σ = 10312268064. Its totient is φ = 10310422200.

The previous prime is 10311345127. The next prime is 10311345139. The reversal of 10311345131 is 13154311301.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13154311301 = 41 ⋅320836861.

It is a cyclic number.

It is not a de Polignac number, because 10311345131 - 2² = 10311345127 is a prime.

It is a super-2 number, since 2×10311345131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10311345097 and 10311345106.

It is not an unprimeable number, because it can be changed into a prime (10311345139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 444500 + ... + 467121.

It is an arithmetic number, because the mean of its divisors is an integer number (2578067016).

Almost surely, 2^10311345131 is an apocalyptic number.

10311345131 is a deficient number, since it is larger than the sum of its proper divisors (922933).

10311345131 is an equidigital number, since it uses as much as digits as its factorization.

10311345131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 922932.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 10311345131 its reverse (13154311301), we get a palindrome (23465656432).

The spelling of 10311345131 in words is "ten billion, three hundred eleven million, three hundred forty-five thousand, one hundred thirty-one".