Base | Representation |
---|---|
bin | 10011001101001101… |
… | …11000011100101001 |
3 | 222121121201120011010 |
4 | 21212212320130221 |
5 | 132104204401210 |
6 | 4423105054133 |
7 | 513345324210 |
oct | 114646703451 |
9 | 28547646133 |
10 | 10311403305 |
11 | 4411577a15 |
12 | 1bb9327349 |
13 | c8437b798 |
14 | 6db664077 |
15 | 4053c0920 |
hex | 2669b8729 |
10311403305 has 16 divisors (see below), whose sum is σ = 18855137664. Its totient is φ = 4713784320.
The previous prime is 10311403237. The next prime is 10311403321. The reversal of 10311403305 is 50330411301.
10311403305 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 10311403305 - 212 = 10311399209 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 49101816 + ... + 49102025.
It is an arithmetic number, because the mean of its divisors is an integer number (1178446104).
Almost surely, 210311403305 is an apocalyptic number.
10311403305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
10311403305 is a deficient number, since it is larger than the sum of its proper divisors (8543734359).
10311403305 is an equidigital number, since it uses as much as digits as its factorization.
10311403305 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 98203856.
The product of its (nonzero) digits is 540, while the sum is 21.
Adding to 10311403305 its reverse (50330411301), we get a palindrome (60641814606).
The spelling of 10311403305 in words is "ten billion, three hundred eleven million, four hundred three thousand, three hundred five".
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