103121200100203 has 4 divisors (see below), whose sum is σ = 106447690426048. Its totient is φ = 99794709774360.

The previous prime is 103121200100201. The next prime is 103121200100231. The reversal of 103121200100203 is 302001002121301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 103121200100203 - 2¹ = 103121200100201 is a prime.

It is a super-4 number, since 4×103121200100203⁴ (a number of 57 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (103121200100201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1663245162876 + ... + 1663245162937.

It is an arithmetic number, because the mean of its divisors is an integer number (26611922606512).

Almost surely, 2^{103121200100203} is an apocalyptic number.

103121200100203 is a deficient number, since it is larger than the sum of its proper divisors (3326490325845).

103121200100203 is an equidigital number, since it uses as much as digits as its factorization.

103121200100203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3326490325844.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 103121200100203 its reverse (302001002121301), we get a palindrome (405122202221504).

The spelling of 103121200100203 in words is "one hundred three trillion, one hundred twenty-one billion, two hundred million, one hundred thousand, two hundred three".