10312131113 has 8 divisors (see below), whose sum is σ = 10565130240. Its totient is φ = 10059202720.

The previous prime is 10312131107. The next prime is 10312131119. The reversal of 10312131113 is 31113121301.

It is an interprime number because it is at equal distance from previous prime (10312131107) and next prime (10312131119).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10312131113 - 2¹⁰ = 10312130089 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10312131091 and 10312131100.

It is not an unprimeable number, because it can be changed into a prime (10312131119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 392648 + ... + 418086.

It is an arithmetic number, because the mean of its divisors is an integer number (1320641280).

Almost surely, 2^10312131113 is an apocalyptic number.

It is an amenable number.

10312131113 is a deficient number, since it is larger than the sum of its proper divisors (252999127).

10312131113 is an equidigital number, since it uses as much as digits as its factorization.

10312131113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35367.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 10312131113 its reverse (31113121301), we get a palindrome (41425252414).

The spelling of 10312131113 in words is "ten billion, three hundred twelve million, one hundred thirty-one thousand, one hundred thirteen".