Base | Representation |
---|---|
bin | 1001011000001111101011… |
… | …1110001100111000111011 |
3 | 1100111211102012212211122211 |
4 | 2112003322332030320323 |
5 | 2322423221310320443 |
6 | 33533154511355551 |
7 | 2113012150524361 |
oct | 226037276147073 |
9 | 40454365784584 |
10 | 10312132120123 |
11 | 3316394821779 |
12 | 11a6688222bb7 |
13 | 59a5785ca422 |
14 | 279177641631 |
15 | 12d39776e19d |
hex | 960faf8ce3b |
10312132120123 has 4 divisors (see below), whose sum is σ = 10312192978560. Its totient is φ = 10312071261688.
The previous prime is 10312132120117. The next prime is 10312132120133. The reversal of 10312132120123 is 32102123121301.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10312132120123 - 217 = 10312131989051 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10312132120094 and 10312132120103.
It is not an unprimeable number, because it can be changed into a prime (10312132120133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30174340 + ... + 30514177.
It is an arithmetic number, because the mean of its divisors is an integer number (2578048244640).
Almost surely, 210312132120123 is an apocalyptic number.
10312132120123 is a deficient number, since it is larger than the sum of its proper divisors (60858437).
10312132120123 is an equidigital number, since it uses as much as digits as its factorization.
10312132120123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 60858436.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 10312132120123 its reverse (32102123121301), we get a palindrome (42414255241424).
The spelling of 10312132120123 in words is "ten trillion, three hundred twelve billion, one hundred thirty-two million, one hundred twenty thousand, one hundred twenty-three".
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