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10312142331 = 35037339323
BaseRepresentation
bin10011001101010011…
…01100110111111011
3222121200010002220110
421212221230313323
5132104402023311
64423132555403
7513354522621
oct114651546773
928550102813
1010312142331
114411a32187
121bb9622b63
13c84579c8a
146db7b7511
154054b98a6
hex266a6cdfb

10312142331 has 16 divisors (see below), whose sum is σ = 13797133056. Its totient is φ = 6850998816.

The previous prime is 10312142329. The next prime is 10312142339. The reversal of 10312142331 is 13324121301.

It is not a de Polignac number, because 10312142331 - 21 = 10312142329 is a prime.

It is a super-2 number, since 2×103121423312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10312142298 and 10312142307.

It is not an unprimeable number, because it can be changed into a prime (10312142339) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1101436 + ... + 1110758.

It is an arithmetic number, because the mean of its divisors is an integer number (862320816).

Almost surely, 210312142331 is an apocalyptic number.

10312142331 is a deficient number, since it is larger than the sum of its proper divisors (3484990725).

10312142331 is an equidigital number, since it uses as much as digits as its factorization.

10312142331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10562.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 10312142331 its reverse (13324121301), we get a palindrome (23636263632).

The spelling of 10312142331 in words is "ten billion, three hundred twelve million, one hundred forty-two thousand, three hundred thirty-one".

Divisors: 1 3 503 733 1509 2199 9323 27969 368699 1106097 4689469 6833759 14068407 20501277 3437380777 10312142331