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10312144131 = 321116290907
BaseRepresentation
bin10011001101010011…
…01101010100000011
3222121200010012101010
421212221231110003
5132104402103011
64423133012003
7513354531102
oct114651552403
928550105333
1010312144131
114411a33573
121bb9624003
13c8457aa43
146db7b8039
154054ba1a6
hex266a6d503

10312144131 has 8 divisors (see below), whose sum is σ = 13814689984. Its totient is φ = 6842180520.

The previous prime is 10312144111. The next prime is 10312144147. The reversal of 10312144131 is 13144121301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10312144131 - 25 = 10312144099 is a prime.

It is a super-2 number, since 2×103121441312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10312144098 and 10312144107.

It is not an unprimeable number, because it can be changed into a prime (10312144111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8144821 + ... + 8146086.

It is an arithmetic number, because the mean of its divisors is an integer number (1726836248).

Almost surely, 210312144131 is an apocalyptic number.

10312144131 is a deficient number, since it is larger than the sum of its proper divisors (3502545853).

10312144131 is a wasteful number, since it uses less digits than its factorization.

10312144131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16291121.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 10312144131 its reverse (13144121301), we get a palindrome (23456265432).

The spelling of 10312144131 in words is "ten billion, three hundred twelve million, one hundred forty-four thousand, one hundred thirty-one".

Divisors: 1 3 211 633 16290907 48872721 3437381377 10312144131