Base | Representation |
---|---|
bin | 11110000000110011000… |
… | …01000101010100111011 |
3 | 10122120202111211122200011 |
4 | 33000121201011110323 |
5 | 113343414341112021 |
6 | 2105422552522351 |
7 | 134334412350523 |
oct | 17003141052473 |
9 | 3576674748604 |
10 | 1031220254011 |
11 | 368379a49912 |
12 | 147a356b03b7 |
13 | 763223c701c |
14 | 37ca8974683 |
15 | 1bc5757bde1 |
hex | f01984553b |
1031220254011 has 4 divisors (see below), whose sum is σ = 1031223109392. Its totient is φ = 1031217398632.
The previous prime is 1031220253979. The next prime is 1031220254021. The reversal of 1031220254011 is 1104520221301.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1031220254011 - 25 = 1031220253979 is a prime.
It is a super-2 number, since 2×10312202540112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1031220254021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 791455 + ... + 1639768.
It is an arithmetic number, because the mean of its divisors is an integer number (257805777348).
Almost surely, 21031220254011 is an apocalyptic number.
1031220254011 is a deficient number, since it is larger than the sum of its proper divisors (2855381).
1031220254011 is an equidigital number, since it uses as much as digits as its factorization.
1031220254011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2855380.
The product of its (nonzero) digits is 480, while the sum is 22.
Adding to 1031220254011 its reverse (1104520221301), we get a palindrome (2135740475312).
The spelling of 1031220254011 in words is "one trillion, thirty-one billion, two hundred twenty million, two hundred fifty-four thousand, eleven".
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