Search a number
-
+
10312301322993 = 33437433774331
BaseRepresentation
bin1001011000010000010100…
…0011101010001011110001
31100111211212000021020100210
42112010011003222023301
52322424043114313433
633533223354134333
72113016303653245
oct226040503521361
940454760236323
1010312301322993
11331647128a35a
1211a6714a213a9
1359a5a4690977
14279191cc8425
1512d3a7543463
hex961050ea2f1

10312301322993 has 4 divisors (see below), whose sum is σ = 13749735097328. Its totient is φ = 6874867548660.

The previous prime is 10312301322943. The next prime is 10312301323019. The reversal of 10312301322993 is 39922310321301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10312301322993 - 26 = 10312301322929 is a prime.

It is a super-2 number, since 2×103123013229932 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10312301322923) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1718716887163 + ... + 1718716887168.

It is an arithmetic number, because the mean of its divisors is an integer number (3437433774332).

Almost surely, 210312301322993 is an apocalyptic number.

It is an amenable number.

10312301322993 is a deficient number, since it is larger than the sum of its proper divisors (3437433774335).

10312301322993 is an equidigital number, since it uses as much as digits as its factorization.

10312301322993 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3437433774334.

The product of its (nonzero) digits is 52488, while the sum is 39.

The spelling of 10312301322993 in words is "ten trillion, three hundred twelve billion, three hundred one million, three hundred twenty-two thousand, nine hundred ninety-three".

Divisors: 1 3 3437433774331 10312301322993