Base | Representation |
---|---|
bin | 10111011100101001001111… |
… | …110100111001010110110001 |
3 | 111112010111210022020021011222 |
4 | 113130221033310321112301 |
5 | 102004033414013342231 |
6 | 1003154141142314425 |
7 | 30502266364352000 |
oct | 2734511764712661 |
9 | 445114708207158 |
10 | 103123504043441 |
11 | 2a949483676742 |
12 | b696038a28a15 |
13 | 4570673ab409b |
14 | 1b672c0582c37 |
15 | bdc72b92427b |
hex | 5dca4fd395b1 |
103123504043441 has 16 divisors (see below), whose sum is σ = 120499733088000. Its totient is φ = 88215845969664.
The previous prime is 103123504043437. The next prime is 103123504043447. The reversal of 103123504043441 is 144340405321301.
It is not a de Polignac number, because 103123504043441 - 22 = 103123504043437 is a prime.
It is not an unprimeable number, because it can be changed into a prime (103123504043447) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 298685936 + ... + 299030993.
It is an arithmetic number, because the mean of its divisors is an integer number (7531233318000).
Almost surely, 2103123504043441 is an apocalyptic number.
It is an amenable number.
103123504043441 is a deficient number, since it is larger than the sum of its proper divisors (17376229044559).
103123504043441 is an frugal number, since it uses more digits than its factorization.
103123504043441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 597717453 (or 597717439 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 103123504043441 its reverse (144340405321301), we get a palindrome (247463909364742).
The spelling of 103123504043441 in words is "one hundred three trillion, one hundred twenty-three billion, five hundred four million, forty-three thousand, four hundred forty-one".
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