1031300220113 has 4 divisors (see below), whose sum is σ = 1031322961920. Its totient is φ = 1031277478308.

The previous prime is 1031300220101. The next prime is 1031300220143. The reversal of 1031300220113 is 3110220031301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1031300220113 - 2⁸ = 1031300219857 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1031300220091 and 1031300220100.

It is not an unprimeable number, because it can be changed into a prime (1031300220143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11302745 + ... + 11393622.

It is an arithmetic number, because the mean of its divisors is an integer number (257830740480).

Almost surely, 2^{1031300220113} is an apocalyptic number.

It is an amenable number.

1031300220113 is a deficient number, since it is larger than the sum of its proper divisors (22741807).

1031300220113 is an equidigital number, since it uses as much as digits as its factorization.

1031300220113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22741806.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1031300220113 its reverse (3110220031301), we get a palindrome (4141520251414).

The spelling of 1031300220113 in words is "one trillion, thirty-one billion, three hundred million, two hundred twenty thousand, one hundred thirteen".