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103130035 = 520626007
BaseRepresentation
bin1100010010110…
…10001110110011
321012001112210221
412021122032303
5202400130120
614122233511
72361406441
oct611321663
9235045727
10103130035
115323a138
122a655897
131849b3b8
14d9a7b91
1590c20aa
hex625a3b3

103130035 has 4 divisors (see below), whose sum is σ = 123756048. Its totient is φ = 82504024.

The previous prime is 103130029. The next prime is 103130051. The reversal of 103130035 is 530031301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 103130035 - 211 = 103127987 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10312999 + ... + 10313008.

It is an arithmetic number, because the mean of its divisors is an integer number (30939012).

Almost surely, 2103130035 is an apocalyptic number.

103130035 is a deficient number, since it is larger than the sum of its proper divisors (20626013).

103130035 is an equidigital number, since it uses as much as digits as its factorization.

103130035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20626012.

The product of its (nonzero) digits is 135, while the sum is 16.

The square root of 103130035 is about 10155.2959090319. The cubic root of 103130035 is about 468.9519956686.

Adding to 103130035 its reverse (530031301), we get a palindrome (633161336).

The spelling of 103130035 in words is "one hundred three million, one hundred thirty thousand, thirty-five".

Divisors: 1 5 20626007 103130035