Base | Representation |
---|---|
bin | 1001011000010011010101… |
… | …0001101011011010010001 |
3 | 1100111220221101111202020011 |
4 | 2112010311101223122101 |
5 | 2322432222214220101 |
6 | 33533435533314521 |
7 | 2113045326124522 |
oct | 226046521533221 |
9 | 40456841452204 |
10 | 10313110304401 |
11 | 33168469a5033 |
12 | 11a68bb935a41 |
13 | 59a6a31698a8 |
14 | 27922b510849 |
15 | 12d403591751 |
hex | 9613546b691 |
10313110304401 has 4 divisors (see below), whose sum is σ = 10855905583600. Its totient is φ = 9770315025204.
The previous prime is 10313110304383. The next prime is 10313110304417. The reversal of 10313110304401 is 10440301131301.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 10313110304401 - 229 = 10312573433489 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10313110304201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 271397639571 + ... + 271397639608.
It is an arithmetic number, because the mean of its divisors is an integer number (2713976395900).
Almost surely, 210313110304401 is an apocalyptic number.
It is an amenable number.
10313110304401 is a deficient number, since it is larger than the sum of its proper divisors (542795279199).
10313110304401 is an equidigital number, since it uses as much as digits as its factorization.
10313110304401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 542795279198.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 10313110304401 its reverse (10440301131301), we get a palindrome (20753411435702).
The spelling of 10313110304401 in words is "ten trillion, three hundred thirteen billion, one hundred ten million, three hundred four thousand, four hundred one".
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