1031312113 has 4 divisors (see below), whose sum is σ = 1110643828. Its totient is φ = 951980400.

The previous prime is 1031312083. The next prime is 1031312131. The reversal of 1031312113 is 3112131301.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3112131301 = 103 ⋅30214867.

It can be written as a sum of positive squares in 2 ways, for example, as 249103089 + 782209024 = 15783^2 + 27968^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1031312113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1031312813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39665838 + ... + 39665863.

It is an arithmetic number, because the mean of its divisors is an integer number (277660957).

Almost surely, 2^1031312113 is an apocalyptic number.

1031312113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1031312113 is a deficient number, since it is larger than the sum of its proper divisors (79331715).

1031312113 is an equidigital number, since it uses as much as digits as its factorization.

1031312113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 79331714.

The product of its (nonzero) digits is 54, while the sum is 16.

The square root of 1031312113 is about 32114.0485301994. The cubic root of 1031312113 is about 1010.3302886709.

Adding to 1031312113 its reverse (3112131301), we get a palindrome (4143443414).

The spelling of 1031312113 in words is "one billion, thirty-one million, three hundred twelve thousand, one hundred thirteen".