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103131213011 = 128980008699
BaseRepresentation
bin110000000001100011…
…0010110110011010011
3100212012101120102222222
41200003012112303103
53142203042304021
6115213335451255
710310454563261
oct1400306266323
9325171512888
10103131213011
113a812976852
1217ba2526b2b
1399574458c8
144dc4c61431
152a3909b6ab
hex1803196cd3

103131213011 has 4 divisors (see below), whose sum is σ = 103211223000. Its totient is φ = 103051203024.

The previous prime is 103131212983. The next prime is 103131213023. The reversal of 103131213011 is 110312131301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 103131213011 - 214 = 103131196627 is a prime.

It is a super-2 number, since 2×1031312130112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (103131213041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40003061 + ... + 40005638.

It is an arithmetic number, because the mean of its divisors is an integer number (25802805750).

Almost surely, 2103131213011 is an apocalyptic number.

103131213011 is a deficient number, since it is larger than the sum of its proper divisors (80009989).

103131213011 is an equidigital number, since it uses as much as digits as its factorization.

103131213011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 80009988.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 103131213011 its reverse (110312131301), we get a palindrome (213443344312).

The spelling of 103131213011 in words is "one hundred three billion, one hundred thirty-one million, two hundred thirteen thousand, eleven".

Divisors: 1 1289 80008699 103131213011