Base | Representation |
---|---|
bin | 11110000000111101111… |
… | …11111000000010010001 |
3 | 10122120222220212121110210 |
4 | 33000132333320002101 |
5 | 113344111411241423 |
6 | 2105440035514333 |
7 | 134336610110121 |
oct | 17003677700221 |
9 | 3576886777423 |
10 | 1031312212113 |
11 | 368416948347 |
12 | 147a604589a9 |
13 | 763384832c1 |
14 | 37cb6c70c81 |
15 | 1bc60693b93 |
hex | f01eff8091 |
1031312212113 has 16 divisors (see below), whose sum is σ = 1408704292800. Its totient is φ = 670732773120.
The previous prime is 1031312212111. The next prime is 1031312212169. The reversal of 1031312212113 is 3112122131301.
1031312212113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 1031312212113 - 21 = 1031312212111 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1031312212113.
It is not an unprimeable number, because it can be changed into a prime (1031312212111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1934653 + ... + 2409461.
It is an arithmetic number, because the mean of its divisors is an integer number (88044018300).
Almost surely, 21031312212113 is an apocalyptic number.
It is an amenable number.
1031312212113 is a deficient number, since it is larger than the sum of its proper divisors (377392080687).
1031312212113 is a wasteful number, since it uses less digits than its factorization.
1031312212113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 492512.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 1031312212113 its reverse (3112122131301), we get a palindrome (4143434343414).
The spelling of 1031312212113 in words is "one trillion, thirty-one billion, three hundred twelve million, two hundred twelve thousand, one hundred thirteen".
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