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10313133615345 = 351162503840093
BaseRepresentation
bin1001011000010011011010…
…1010100110100011110001
31100111221000000101001211110
42112010312222212203301
52322432244201142340
633533442125103533
72113046031223461
oct226046652464361
940457000331743
1010313133615345
113316859076980
1211a69076b7ba9
1359a6a7c3c052
1427923065bba1
1512d405648680
hex96136aa68f1

10313133615345 has 16 divisors (see below), whose sum is σ = 18001105947072. Its totient is φ = 5000307207360.

The previous prime is 10313133615283. The next prime is 10313133615361. The reversal of 10313133615345 is 54351633131301.

It is not a de Polignac number, because 10313133615345 - 27 = 10313133615217 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 31251919882 + ... + 31251920211.

It is an arithmetic number, because the mean of its divisors is an integer number (1125069121692).

Almost surely, 210313133615345 is an apocalyptic number.

10313133615345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

10313133615345 is a deficient number, since it is larger than the sum of its proper divisors (7687972331727).

10313133615345 is a wasteful number, since it uses less digits than its factorization.

10313133615345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62503840112.

The product of its (nonzero) digits is 145800, while the sum is 39.

Adding to 10313133615345 its reverse (54351633131301), we get a palindrome (64664766746646).

The spelling of 10313133615345 in words is "ten trillion, three hundred thirteen billion, one hundred thirty-three million, six hundred fifteen thousand, three hundred forty-five".

Divisors: 1 3 5 11 15 33 55 165 62503840093 187511520279 312519200465 687542241023 937557601395 2062626723069 3437711205115 10313133615345