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103131433 = 206349991
BaseRepresentation
bin1100010010110…
…10100100101001
321012001121201201
412021122210221
5202400201213
614122244201
72361413506
oct611324451
9235047651
10103131433
1153240199
122a656661
131849bc22
14d9a84ad
1590c26dd
hex625a929

103131433 has 4 divisors (see below), whose sum is σ = 103183488. Its totient is φ = 103079380.

The previous prime is 103131397. The next prime is 103131439. The reversal of 103131433 is 334131301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 103131433 - 29 = 103130921 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 103131433.

It is not an unprimeable number, because it can be changed into a prime (103131439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22933 + ... + 27058.

It is an arithmetic number, because the mean of its divisors is an integer number (25795872).

Almost surely, 2103131433 is an apocalyptic number.

It is an amenable number.

103131433 is a deficient number, since it is larger than the sum of its proper divisors (52055).

103131433 is an equidigital number, since it uses as much as digits as its factorization.

103131433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 52054.

The product of its (nonzero) digits is 324, while the sum is 19.

The square root of 103131433 is about 10155.3647398801. The cubic root of 103131433 is about 468.9541146502.

Adding to 103131433 its reverse (334131301), we get a palindrome (437262734).

The spelling of 103131433 in words is "one hundred three million, one hundred thirty-one thousand, four hundred thirty-three".

Divisors: 1 2063 49991 103131433