103132112113 has 4 divisors (see below), whose sum is σ = 103329305968. Its totient is φ = 102934918260.

The previous prime is 103132112101. The next prime is 103132112191. The reversal of 103132112113 is 311211231301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311211231301 = 29 ⋅10731421769.

It is a cyclic number.

It is not a de Polignac number, because 103132112113 - 2⁹ = 103132111601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (103132110113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 98596143 + ... + 98597188.

It is an arithmetic number, because the mean of its divisors is an integer number (25832326492).

Almost surely, 2^103132112113 is an apocalyptic number.

It is an amenable number.

103132112113 is a deficient number, since it is larger than the sum of its proper divisors (197193855).

103132112113 is an equidigital number, since it uses as much as digits as its factorization.

103132112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 197193854.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 103132112113 its reverse (311211231301), we get a palindrome (414343343414).

The spelling of 103132112113 in words is "one hundred three billion, one hundred thirty-two million, one hundred twelve thousand, one hundred thirteen".