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10313313001 = 16076417743
BaseRepresentation
bin10011001101011100…
…01010101011101001
3222121202022120202121
421212232022223221
5132110202004001
64423214031241
7513400466635
oct114656125351
928552276677
1010313313001
114412661782
121bb9aa8521
13c84899a94
146db9dddc5
1540564b6a1
hex266b8aae9

10313313001 has 4 divisors (see below), whose sum is σ = 10319732352. Its totient is φ = 10306893652.

The previous prime is 10313312987. The next prime is 10313313013. The reversal of 10313313001 is 10031331301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10313313001 - 29 = 10313312489 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10313314001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3207265 + ... + 3210478.

It is an arithmetic number, because the mean of its divisors is an integer number (2579933088).

Almost surely, 210313313001 is an apocalyptic number.

It is an amenable number.

10313313001 is a deficient number, since it is larger than the sum of its proper divisors (6419351).

10313313001 is an equidigital number, since it uses as much as digits as its factorization.

10313313001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6419350.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 10313313001 its reverse (10031331301), we get a palindrome (20344644302).

It can be divided in two parts, 1031331300 and 1, that added together give a palindrome (1031331301).

The spelling of 10313313001 in words is "ten billion, three hundred thirteen million, three hundred thirteen thousand, one".

Divisors: 1 1607 6417743 10313313001