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10313404131 = 34817713681
BaseRepresentation
bin10011001101011101…
…00000111011100011
3222121202111012202210
421212232200323203
5132110212413011
64423220013203
7513401326422
oct114656407343
928552435683
1010313404131
114412714198
121bb9b31203
13c848cc3c4
146dba252b9
154056686a6
hex266ba0ee3

10313404131 has 8 divisors (see below), whose sum is σ = 13754079504. Its totient is φ = 6874165760.

The previous prime is 10313404103. The next prime is 10313404147. The reversal of 10313404131 is 13140431301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10313404131 - 211 = 10313402083 is a prime.

It is a super-2 number, since 2×103134041312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10313404098 and 10313404107.

It is not an unprimeable number, because it can be changed into a prime (10313404181) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 342390 + ... + 371291.

It is an arithmetic number, because the mean of its divisors is an integer number (1719259938).

Almost surely, 210313404131 is an apocalyptic number.

10313404131 is a deficient number, since it is larger than the sum of its proper divisors (3440675373).

10313404131 is an equidigital number, since it uses as much as digits as its factorization.

10313404131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 718501.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 10313404131 its reverse (13140431301), we get a palindrome (23453835432).

The spelling of 10313404131 in words is "ten billion, three hundred thirteen million, four hundred four thousand, one hundred thirty-one".

Divisors: 1 3 4817 14451 713681 2141043 3437801377 10313404131