1031404414131 has 72 divisors (see below), whose sum is σ = 1940718923520. Its totient is φ = 515403839808.

The previous prime is 1031404414127. The next prime is 1031404414153. The reversal of 1031404414131 is 1314144041301.

1031404414131 is a `hidden beast` number, since 10 + 3 + 140 + 441 + 41 + 31 = 666.

1031404414131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 1031404414131 - 2² = 1031404414127 is a prime.

It is a super-2 number, since 2×1031404414131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1031404414095 and 1031404414104.

It is not an unprimeable number, because it can be changed into a prime (1031404414121) by changing a digit.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 2346991 + ... + 2751576.

Almost surely, 2^{1031404414131} is an apocalyptic number.

1031404414131 is a deficient number, since it is larger than the sum of its proper divisors (909314509389).

1031404414131 is a wasteful number, since it uses less digits than its factorization.

1031404414131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5098625 (or 5098609 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

Adding to 1031404414131 its reverse (1314144041301), we get a palindrome (2345548455432).

The spelling of 1031404414131 in words is "one trillion, thirty-one billion, four hundred four million, four hundred fourteen thousand, one hundred thirty-one".