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103142113 = 619166627
BaseRepresentation
bin1100010010111…
…01001011100001
321012002011101021
412021131023201
5202401021423
614122405441
72361456604
oct611351341
9235064337
10103142113
1153248218
122a660881
13184a3a49
14d9ac33b
1590c595d
hex625d2e1

103142113 has 4 divisors (see below), whose sum is σ = 103309360. Its totient is φ = 102974868.

The previous prime is 103142093. The next prime is 103142131. The reversal of 103142113 is 311241301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-103142113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (103142173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82695 + ... + 83932.

It is an arithmetic number, because the mean of its divisors is an integer number (25827340).

Almost surely, 2103142113 is an apocalyptic number.

It is an amenable number.

103142113 is a deficient number, since it is larger than the sum of its proper divisors (167247).

103142113 is an equidigital number, since it uses as much as digits as its factorization.

103142113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 167246.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 103142113 is about 10155.8905567163. The cubic root of 103142113 is about 468.9703019461.

Adding to 103142113 its reverse (311241301), we get a palindrome (414383414).

The spelling of 103142113 in words is "one hundred three million, one hundred forty-two thousand, one hundred thirteen".

Divisors: 1 619 166627 103142113