Base | Representation |
---|---|
bin | 11110000001001100001… |
… | …01000011111100100011 |
3 | 10122121022012102021110110 |
4 | 33000212011003330203 |
5 | 113344332314342011 |
6 | 2105455522102403 |
7 | 134342551642632 |
oct | 17004605037443 |
9 | 3577265367413 |
10 | 1031431012131 |
11 | 368477a0a583 |
12 | 147a941aaa03 |
13 | 76356c79c80 |
14 | 37cc8957519 |
15 | 1bc6ad0dba6 |
hex | f026143f23 |
1031431012131 has 16 divisors (see below), whose sum is σ = 1501317220256. Its totient is φ = 626031887616.
The previous prime is 1031431012121. The next prime is 1031431012133. The reversal of 1031431012131 is 1312101341301.
It is not a de Polignac number, because 1031431012131 - 211 = 1031431010083 is a prime.
It is a super-2 number, since 2×10314310121312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1031431012098 and 1031431012107.
It is not an unprimeable number, because it can be changed into a prime (1031431012133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 181140640 + ... + 181146333.
It is an arithmetic number, because the mean of its divisors is an integer number (93832326266).
Almost surely, 21031431012131 is an apocalyptic number.
1031431012131 is a deficient number, since it is larger than the sum of its proper divisors (469886208125).
1031431012131 is a wasteful number, since it uses less digits than its factorization.
1031431012131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 362287062.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 1031431012131 its reverse (1312101341301), we get a palindrome (2343532353432).
The spelling of 1031431012131 in words is "one trillion, thirty-one billion, four hundred thirty-one million, twelve thousand, one hundred thirty-one".
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