10314433 has 4 divisors (see below), whose sum is σ = 10374228. Its totient is φ = 10254640.

The previous prime is 10314431. The next prime is 10314443. The reversal of 10314433 is 33441301.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33441301 = 3083 ⋅10847.

It can be written as a sum of positive squares in 2 ways, for example, as 9042049 + 1272384 = 3007^2 + 1128^2 .

It is a cyclic number.

It is not a de Polignac number, because 10314433 - 2¹ = 10314431 is a prime.

It is a super-2 number, since 2×10314433² = 212775056222978, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10314433.

It is not an unprimeable number, because it can be changed into a prime (10314431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29638 + ... + 29983.

It is an arithmetic number, because the mean of its divisors is an integer number (2593557).

Almost surely, 2^10314433 is an apocalyptic number.

It is an amenable number.

10314433 is a deficient number, since it is larger than the sum of its proper divisors (59795).

10314433 is an equidigital number, since it uses as much as digits as its factorization.

10314433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59794.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 10314433 is about 3211.6090982559. The cubic root of 10314433 is about 217.6782912956.

Adding to 10314433 its reverse (33441301), we get a palindrome (43755734).

The spelling of 10314433 in words is "ten million, three hundred fourteen thousand, four hundred thirty-three".