Base | Representation |
---|---|
bin | 10011001101100100… |
… | …11100001011010011 |
3 | 222121211102111102202 |
4 | 21212302130023103 |
5 | 132110443330420 |
6 | 4423254033415 |
7 | 513413143631 |
oct | 114662341323 |
9 | 28554374382 |
10 | 10314433235 |
11 | 4413257397 |
12 | 1bba34886b |
13 | c84b9c942 |
14 | 6dbc12351 |
15 | 4057bd575 |
hex | 266c9c2d3 |
10314433235 has 8 divisors (see below), whose sum is σ = 12405262320. Its totient is φ = 8232918304.
The previous prime is 10314433229. The next prime is 10314433249. The reversal of 10314433235 is 53233441301.
10314433235 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10314433235 - 210 = 10314432211 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10314433198 and 10314433207.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2326100 + ... + 2330529.
It is an arithmetic number, because the mean of its divisors is an integer number (1550657790).
Almost surely, 210314433235 is an apocalyptic number.
10314433235 is a deficient number, since it is larger than the sum of its proper divisors (2090829085).
10314433235 is an equidigital number, since it uses as much as digits as its factorization.
10314433235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4657077.
The product of its (nonzero) digits is 12960, while the sum is 29.
Adding to 10314433235 its reverse (53233441301), we get a palindrome (63547874536).
The spelling of 10314433235 in words is "ten billion, three hundred fourteen million, four hundred thirty-three thousand, two hundred thirty-five".
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