10315302121 has 4 divisors (see below), whose sum is σ = 10555192912. Its totient is φ = 10075411332.

The previous prime is 10315302079. The next prime is 10315302133. The reversal of 10315302121 is 12120351301.

10315302121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12120351301 = 15377 ⋅788213.

It is a cyclic number.

It is not a de Polignac number, because 10315302121 - 2¹⁵ = 10315269353 is a prime.

It is a super-3 number, since 3×10315302121³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10315302161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 119945331 + ... + 119945416.

It is an arithmetic number, because the mean of its divisors is an integer number (2638798228).

Almost surely, 2^10315302121 is an apocalyptic number.

It is an amenable number.

10315302121 is a deficient number, since it is larger than the sum of its proper divisors (239890791).

10315302121 is an equidigital number, since it uses as much as digits as its factorization.

10315302121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 239890790.

The product of its (nonzero) digits is 180, while the sum is 19.

Adding to 10315302121 its reverse (12120351301), we get a palindrome (22435653422).

The spelling of 10315302121 in words is "ten billion, three hundred fifteen million, three hundred two thousand, one hundred twenty-one".