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103230120113 = 613971173431
BaseRepresentation
bin110000000100011111…
…1101010000010110001
3100212110021200110000222
41200020333222002301
53142403402320423
6115231231422425
710313065354211
oct1401077520261
9325407613028
10103230120113
113a86379115a
121800b684a15
139971a95b13
144dd404a241
152a42ad73c8
hex1808fea0b1

103230120113 has 8 divisors (see below), whose sum is σ = 103505605056. Its totient is φ = 102954985200.

The previous prime is 103230120109. The next prime is 103230120131. The reversal of 103230120113 is 311021032301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 103230120113 - 22 = 103230120109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103230120091 and 103230120100.

It is not an unprimeable number, because it can be changed into a prime (103230120143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 508508 + ... + 681938.

It is an arithmetic number, because the mean of its divisors is an integer number (12938200632).

Almost surely, 2103230120113 is an apocalyptic number.

It is an amenable number.

103230120113 is a deficient number, since it is larger than the sum of its proper divisors (275484943).

103230120113 is an equidigital number, since it uses as much as digits as its factorization.

103230120113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 175015.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 103230120113 its reverse (311021032301), we get a palindrome (414251152414).

The spelling of 103230120113 in words is "one hundred three billion, two hundred thirty million, one hundred twenty thousand, one hundred thirteen".

Divisors: 1 613 971 173431 595223 106313203 168401501 103230120113