10324113 has 4 divisors (see below), whose sum is σ = 13765488. Its totient is φ = 6882740.

The previous prime is 10324099. The next prime is 10324129. The reversal of 10324113 is 31142301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31142301 = 3 ⋅10380767.

It is a cyclic number.

It is not a de Polignac number, because 10324113 - 2⁵ = 10324081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10324092 and 10324101.

It is not an unprimeable number, because it can be changed into a prime (10324313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1720683 + ... + 1720688.

It is an arithmetic number, because the mean of its divisors is an integer number (3441372).

Almost surely, 2^10324113 is an apocalyptic number.

It is an amenable number.

10324113 is a deficient number, since it is larger than the sum of its proper divisors (3441375).

10324113 is an equidigital number, since it uses as much as digits as its factorization.

10324113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3441374.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 10324113 is about 3213.1157775592. The cubic root of 10324113 is about 217.7463663586.

Adding to 10324113 its reverse (31142301), we get a palindrome (41466414).

The spelling of 10324113 in words is "ten million, three hundred twenty-four thousand, one hundred thirteen".