1033120000113 has 4 divisors (see below), whose sum is σ = 1377493333488. Its totient is φ = 688746666740.

The previous prime is 1033120000097. The next prime is 1033120000141. The reversal of 1033120000113 is 3110000213301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1033120000113 - 2⁴ = 1033120000097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1033120000092 and 1033120000101.

It is not an unprimeable number, because it can be changed into a prime (1033120000013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 172186666683 + ... + 172186666688.

It is an arithmetic number, because the mean of its divisors is an integer number (344373333372).

Almost surely, 2^{1033120000113} is an apocalyptic number.

It is an amenable number.

1033120000113 is a deficient number, since it is larger than the sum of its proper divisors (344373333375).

1033120000113 is an equidigital number, since it uses as much as digits as its factorization.

1033120000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 344373333374.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 1033120000113 its reverse (3110000213301), we get a palindrome (4143120213414).

The spelling of 1033120000113 in words is "one trillion, thirty-three billion, one hundred twenty million, one hundred thirteen", and thus it is an aban number.