103313100113 has 4 divisors (see below), whose sum is σ = 106105346100. Its totient is φ = 100520854128.

The previous prime is 103313100109. The next prime is 103313100167. The reversal of 103313100113 is 311001313301.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 94456031569 + 8857068544 = 307337^2 + 94112^2 .

It is a cyclic number.

It is not a de Polignac number, because 103313100113 - 2² = 103313100109 is a prime.

It is a super-2 number, since 2×103313100113² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103313100091 and 103313100100.

It is not an unprimeable number, because it can be changed into a prime (103313100173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1396122938 + ... + 1396123011.

It is an arithmetic number, because the mean of its divisors is an integer number (26526336525).

Almost surely, 2^103313100113 is an apocalyptic number.

It is an amenable number.

103313100113 is a deficient number, since it is larger than the sum of its proper divisors (2792245987).

103313100113 is an equidigital number, since it uses as much as digits as its factorization.

103313100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2792245986.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 103313100113 its reverse (311001313301), we get a palindrome (414314413414).

The spelling of 103313100113 in words is "one hundred three billion, three hundred thirteen million, one hundred thousand, one hundred thirteen".