Base | Representation |
---|---|
bin | 10111011111111101100001… |
… | …011101110010011011000001 |
3 | 111112221022010002020020221010 |
4 | 113133331201131302123001 |
5 | 102021302213402223210 |
6 | 1003450554252151133 |
7 | 30524615601521523 |
oct | 2737754135623301 |
9 | 445838102206833 |
10 | 103351433242305 |
11 | 2aa27107776376 |
12 | b712249a684a9 |
13 | 4588cc9461921 |
14 | 1b74343a63a13 |
15 | be361bcc6920 |
hex | 5dff617726c1 |
103351433242305 has 16 divisors (see below), whose sum is σ = 165469462565760. Its totient is φ = 55085041269888.
The previous prime is 103351433242289. The next prime is 103351433242307. The reversal of 103351433242305 is 503242334153301.
It is not a de Polignac number, because 103351433242305 - 24 = 103351433242289 is a prime.
It is not an unprimeable number, because it can be changed into a prime (103351433242307) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2232671460 + ... + 2232717749.
It is an arithmetic number, because the mean of its divisors is an integer number (10341841410360).
Almost surely, 2103351433242305 is an apocalyptic number.
103351433242305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
103351433242305 is a deficient number, since it is larger than the sum of its proper divisors (62118029323455).
103351433242305 is a wasteful number, since it uses less digits than its factorization.
103351433242305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4465390760.
The product of its (nonzero) digits is 388800, while the sum is 39.
Adding to 103351433242305 its reverse (503242334153301), we get a palindrome (606593767395606).
The spelling of 103351433242305 in words is "one hundred three trillion, three hundred fifty-one billion, four hundred thirty-three million, two hundred forty-two thousand, three hundred five".
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