103353302544451 has 4 divisors (see below), whose sum is σ = 103354015633072. Its totient is φ = 103352589455832.

The previous prime is 103353302544379. The next prime is 103353302544469. The reversal of 103353302544451 is 154445203353301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 103353302544451 - 2¹³ = 103353302536259 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103353302544398 and 103353302544407.

It is not an unprimeable number, because it can be changed into a prime (103353302584451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 356326860 + ... + 356616793.

It is an arithmetic number, because the mean of its divisors is an integer number (25838503908268).

Almost surely, 2^{103353302544451} is an apocalyptic number.

103353302544451 is a deficient number, since it is larger than the sum of its proper divisors (713088621).

103353302544451 is an equidigital number, since it uses as much as digits as its factorization.

103353302544451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 713088620.

The product of its (nonzero) digits is 1296000, while the sum is 43.

Adding to 103353302544451 its reverse (154445203353301), we get a palindrome (257798505897752).

The spelling of 103353302544451 in words is "one hundred three trillion, three hundred fifty-three billion, three hundred two million, five hundred forty-four thousand, four hundred fifty-one".