10343031441131 has 4 divisors (see below), whose sum is σ = 10887401517000. Its totient is φ = 9798661365264.

The previous prime is 10343031441121. The next prime is 10343031441199. The reversal of 10343031441131 is 13114413034301.

10343031441131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10343031441131 is a prime.

It is a super-2 number, since 2×10343031441131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10343031441094 and 10343031441103.

It is not an unprimeable number, because it can be changed into a prime (10343031441121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 272185037906 + ... + 272185037943.

It is an arithmetic number, because the mean of its divisors is an integer number (2721850379250).

Almost surely, 2^{10343031441131} is an apocalyptic number.

10343031441131 is a deficient number, since it is larger than the sum of its proper divisors (544370075869).

10343031441131 is an equidigital number, since it uses as much as digits as its factorization.

10343031441131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 544370075868.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 10343031441131 its reverse (13114413034301), we get a palindrome (23457444475432).

The spelling of 10343031441131 in words is "ten trillion, three hundred forty-three billion, thirty-one million, four hundred forty-one thousand, one hundred thirty-one".