Base | Representation |
---|---|
bin | 110000001010011111… |
… | …1010000010111110011 |
3 | 100212222022022112221222 |
4 | 1200110333100113303 |
5 | 3143311410412210 |
6 | 115303220335255 |
7 | 10321060616513 |
oct | 1402477202763 |
9 | 325868275858 |
10 | 103431341555 |
11 | 3a957328873 |
12 | 18066b4452b |
13 | 99a468a069 |
14 | 5012a69843 |
15 | 2a555d3655 |
hex | 1814fd05f3 |
103431341555 has 4 divisors (see below), whose sum is σ = 124117609872. Its totient is φ = 82745073240.
The previous prime is 103431341539. The next prime is 103431341567. The reversal of 103431341555 is 555143134301.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 555143134301 = 7 ⋅79306162043.
It is not a de Polignac number, because 103431341555 - 24 = 103431341539 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10343134151 + ... + 10343134160.
It is an arithmetic number, because the mean of its divisors is an integer number (31029402468).
Almost surely, 2103431341555 is an apocalyptic number.
103431341555 is a deficient number, since it is larger than the sum of its proper divisors (20686268317).
103431341555 is an equidigital number, since it uses as much as digits as its factorization.
103431341555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20686268316.
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 103431341555 its reverse (555143134301), we get a palindrome (658574475856).
The spelling of 103431341555 in words is "one hundred three billion, four hundred thirty-one million, three hundred forty-one thousand, five hundred fifty-five".
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