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1034331121211 = 9471092218713
BaseRepresentation
bin11110000110100101111…
…00000110011000111011
310122212210022111002012212
433003102330012120323
5113421302231334321
62111055401325335
7134504455316303
oct17032274063073
93585708432185
101034331121211
11369725a53443
1214856349684b
13766c9a5854b
14380c1b9a603
151bd8a72055b
hexf0d2f0663b

1034331121211 has 4 divisors (see below), whose sum is σ = 1035423340872. Its totient is φ = 1033238901552.

The previous prime is 1034331121139. The next prime is 1034331121277. The reversal of 1034331121211 is 1121211334301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1034331121211 - 234 = 1017151252027 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1034331121111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 546108410 + ... + 546110303.

It is an arithmetic number, because the mean of its divisors is an integer number (258855835218).

Almost surely, 21034331121211 is an apocalyptic number.

1034331121211 is a deficient number, since it is larger than the sum of its proper divisors (1092219661).

1034331121211 is an equidigital number, since it uses as much as digits as its factorization.

1034331121211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1092219660.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 1034331121211 its reverse (1121211334301), we get a palindrome (2155542455512).

The spelling of 1034331121211 in words is "one trillion, thirty-four billion, three hundred thirty-one million, one hundred twenty-one thousand, two hundred eleven".

Divisors: 1 947 1092218713 1034331121211